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Question
The differential equation of all parabolas whose axis is Y-axis, is ______.
Options
`x (d^2y)/(dx^2) - dy/dx` = 0
`x (d^2y)/(dx^2) + dy/dx` = 0
`(d^2y)/(dx^2) - y` = 0
`(d^2y)/(dx^2) - dy/dx` = 0
MCQ
Fill in the Blanks
Solution
The differential equation of all parabolas whose axis is Y-axis, is `underlinebb(x (d^2y)/(dx^2) - dy/dx = 0)`.
Explanation:
Let vertex of parabola be (0, k) as axis of parabola is Y-axis
So, equation of parabola is
(x – 0)2 = 4a (y – k)
`\implies` x2 = 4ay – 4ak
After, differentiating both sides w.r.t., 'x', we get
2x = `4a dy/dx`
Therefore, `1/(2a) = 1/x dy/dx`
Again differentiating on both sides w.r.t. 'x', we get
`d/dx(1/x, dy/dx) = d/dx(1/(2a))`
`\implies 1/x.(d^2y)/(dx^2) + dy/dx(-1/x^2)` = 0
Hence, `x (d^2y)/(dx^2) - dy/dx` = 0
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Formation of Differential Equations
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