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Question
The digit in the tens place of a two-digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is ______.
Options
11b + 30
10b + 30
11b + 3
10b + 3
Solution
The digit in the tens place of a two-digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is 11b + 30.
Explanation:
We take unit place to be b.
So, the digit at ten’s place = (3 + b)
Hence, number = 10(3 + b) + b – 30 + 10b + b = 11b + 30.
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