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Question
The dimensions of self or mutual inductance are given as ______.
Options
[L-2 M1 T-2 l-2]
[L2 M2 T -2 l-2]
[L2 M1 T -2 l -2]
[L2 M2 T -2 l2]
MCQ
Fill in the Blanks
Solution
The dimensions of self or mutual inductance are given as [L2 M1 T -2 l -2].
Explanation:
The self or mutual inductance of a coil is the flux change due to change in current, i.e.
L or M = `phi/"l"`
So, dimensions of Mutual Inductance or
Self-Inductance can be given by
`=> ["L"] = ([phi])/(["l"])`
`= (["ML"^2 "T"^-2 "l"^-1])/(["M"^0 "L"^0 "l"^1])`
`= ["ML"^2 "T"^-2 "l"^-2]`
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