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Question
The dipole moments of CCl4, CHCl3 and CH4 are in the order:
Options
CHCl3 < CH4 = CCl4
CCl4 < CH4 < CHCl3
CH4 < CCl4 < CHCl3
CH4 = CCl4 < CHCl3
MCQ
Solution
CH4 = CCl4 < CHCl3
Explanation:
\[\ce{µ_{CCl_{4}}}\] = \[\ce{µ_{CH_{4}}}\] = 0 due to symmetrical structure but \[\ce{µ_{CHCl_{3}}}\] ≠ 0.
So dipole moment order is CH4 = CCl4 < CHCl3.
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