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The disproportionation of \\ce{MnO^{2-}_4}\ in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, -

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Question

The disproportionation of \[\ce{MnO^{2-}_4}\] in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (µ) value of B in BM is ______. (Nearest integer)

Options

  • 6

  • 4

  • 7

  • 9

MCQ
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Solution

The disproportionation of \[\ce{MnO^{2-}_4}\] in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (µ) value of B in BM is 4.

Explanation:

\[\ce{MnO^{2-}_4 ->[H+] MnO^-_2 + MnO2}\]

No. of unpaired e-(n) = 3

`therefore mu = sqrt("n"("n + 2")) = sqrt15 = 3.877` B. M. ≈ 4 B. M.

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