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The distance between two particles is decreasing at the rate of 6 m/s. If these particles travel with same speed and in the same direction, then the separation increases at the rate of 4 m/s. -

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Question

The distance between two particles is decreasing at the rate of 6 m/s. If these particles travel with same speed and in the same direction, then the separation increases at the rate of 4 m/s. The particles have speed respectively as

Options

  • 5 m/s; 1 m/s

  • 4 m/s; 1 m/s

  • 4 m/s; 2 m/s

  • 5 m/s; 2 m/s

MCQ

Solution

5 m/s; 1 m/s

Explanation:

When two particles approach each other, their relative speed increases.

v = v1 + v2 = 6 m/s  .....(i)

When all of these particles move in the same direction,

v = v1 – v2 = 4 m/s  ......(ii)

On solving, v1 = 5 m/s and v2 = 1 m/s.

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