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Question
The distribution of a sample of students appearing for a C.A. examination is:
Marks | 0 – 100 | 100 – 200 | 200 – 300 | 300 – 400 | 400 – 500 | 500 – 600 |
No. of students | 130 | 150 | 190 | 220 | 280 | 130 |
Help C.A. institute to decide cut-off marks for qualifying an examination when 3% of students pass the examination.
Solution
To decide cut off marks for qualifying an examination when 3% of students pass, we have to find P97.
We construct the less than cumulative frequency table as given below:
Marks | No. of students (f) |
Less than cumulative frequency (c.f.) |
0 – 100 | 130 | 130 |
100 – 200 | 150 | 280 |
200 – 300 | 190 | 470 |
300 – 400 | 220 | 690 |
400 – 500 | 280 | 970 |
500 – 600 | 130 | 1100 ← P97 |
Total | 1100 |
Here, N = 1100
P97 class = class containing `((97"N")/100)^"th"` observation
∴ `(97"N")/100=(97×1100)/100` = 1067
Cumulative frequency which is just greater than (or equal) to 1067 is 1100.
∴ P97 lies in the class 500 – 600
∴ L = 500, h = 100, f = 130, c.f. = 970
∴ P97 = `"L" + "h"/"f" ((97"N")/100 - "c.f.")`
= `500 + 100/130 (1067 - 970)`
= `500 + 10/13 (97)`
= 500 + 74.62
= 574.62 ≈ 575
∴ The cut-off marks for qualifying an examination is 575.
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