Advertisements
Advertisements
Question
The domain of the function cos-1 (log2(x2 + 5x + 8)) is
Options
[2, 3]
[-2, 2]
[3, 1]
[-3, -2]
MCQ
Solution
[-3, -2]
Explanation:
- 1 ≤ log2(x2 + 5x + 8) ≤ 1
`=> 1/2 ≤ (x^2 + 5x + 8) ≤ 2`
`=> x^2 + 5x + 15/2 >= 0`
`=> x^2 + 2(5/2)x + (5/2)^2 - (5/2)^2 + 15/2 >=0`
`=> (x + 5/2)^2 + 5/4 >= 0 and x^2 + 5x + 6 <= 0`
⇒ (x + 3)(x + 2) ≤ 0
⇒ x ∈ [-3, -2]
shaalaa.com
Continuity in the Domain of the Function
Is there an error in this question or solution?