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Question
The dual of (X' + 1) · (Y' + 0) = Y' is ______.
Options
X · 0 + Y · 1 = Y
X' · 1 + Y' · 0 = Y
X' · 0 + Y' · 1 = Y
(X' + 0) + (Y' + 1) = Y'
Solution
The dual of (X' + 1) · (Y' + 0) = Y' is X' · 0 + Y' · 1 = Y.
Explanation:
According to the duality principle, all 1's are changed to 0 and 0's to 1's. All '+' are changed to '·' and all '·' are changed to '+'.
Here is the expression: (X' + 1) · (Y' + 0) = Y'
Dual is : (X' · 0) + (Y' · 1) = Y'
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