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The eccentricity of the hyperbola x2 – 3y2 = 2x + 8 is ______. -

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Question

The eccentricity of the hyperbola x2 – 3y2 = 2x + 8 is ______.

Options

  • `2/3`

  • `1/3`

  • `2/sqrt(3)`

  • `3/2`

MCQ
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Solution

The eccentricity of the hyperbola x2 – 3y2 = 2x + 8 is `underlinebb(2/sqrt(3))`.

Explanation:

The given equation reduces to `(x - 1)^2/9 - y^2/3` = 1.

Thus a2 = 9, b2 = 3

Using b2 = a2 (e2 – 1), we get

3 = 9(e2 – 1) `\implies` e = `2/sqrt(3)`.

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Conic Sections - Hyperbola
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