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Question
The eccentricity of the hyperbola x2 – 3y2 = 2x + 8 is ______.
Options
`2/3`
`1/3`
`2/sqrt(3)`
`3/2`
MCQ
Fill in the Blanks
Solution
The eccentricity of the hyperbola x2 – 3y2 = 2x + 8 is `underlinebb(2/sqrt(3))`.
Explanation:
The given equation reduces to `(x - 1)^2/9 - y^2/3` = 1.
Thus a2 = 9, b2 = 3
Using b2 = a2 (e2 – 1), we get
3 = 9(e2 – 1) `\implies` e = `2/sqrt(3)`.
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Conic Sections - Hyperbola
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