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Question
The empirical formula and molecular mass of a compound are \[\ce{CH2O}\] and 180 g respectively. What will be the molecular formula of the compound?
Options
\[\ce{C9H18O9}\]
\[\ce{CH2O}\]
\[\ce{C6H12O6}\]
\[\ce{C2H4O2}\]
MCQ
Solution
\[\ce{C6H12O6}\]
Explanation:
The empirical formula mass of \[\ce{CH2O}\] is 30 g.
The relation between empirical and molecular formula is given as,
n = `"Molecular formula mass"/"Empirical formula mass"` ......(1)
On substituting the values in equation (1),
n = `(180 g)/(30 g)` = 6
Thus, the molecular formula of the compound will be,
Molecular formula of the compound = \[\ce{(CH2O) = C6H12O6}\]
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