Question

The end product C of the following reaction is

$$\mathrm{C}{\phantom{A}}_2\mathrm{H}{\phantom{A}}_5\mathrm{NH}{\phantom{A}}_2\stackrel{\mathrm{HNO}{\phantom{A}}_2}{\to }\mathrm{A}\stackrel{\mathrm{PCl}{\phantom{A}}_5}{\to }\mathrm{B}\underset{\mathrm{Alcohol}}{\overset{\mathrm{NH}{\phantom{A}}_3}{\to }}\mathrm{C}$$

Options

• Nitroethane

• Ethanol

• Chloroethane

• Ethanamine

Answer 1

Ethanamine

Explanation:

When ethylamine combines with nitrous acid, it produces ethanol as well as N₂ gas. Ethanol and phosphorus pentachloride react to generate ethyl chloride (C₂H₅CI), which then reacts with ammonia (NH₃) to form ethanamine. It's a reaction with two displacements.

$$\underset{\text{Ethanamine}}{\mathrm{C}{\phantom{A}}_2\mathrm{H}{\phantom{A}}_5\mathrm{NH}{\phantom{A}}_2}\stackrel{\mathrm{HNO}{\phantom{A}}_2}{\to }\underset{\text{(A)}}{\underset{\text{Ethanol}}{\mathrm{C}{\phantom{A}}_2\mathrm{H}{\phantom{A}}_5\mathrm{OH}}}\stackrel{\mathrm{PCl}{\phantom{A}}_5}{\to }\underset{\text{(B)}}{\underset{\text{Chloroethane}}{\mathrm{C}{\phantom{A}}_2\mathrm{H}{\phantom{A}}_5\mathrm{Cl}}}\underset{\mathrm{Alcohol}}{\overset{\mathrm{NH}{\phantom{A}}_3}{\to }}\underset{\text{(C)}}{\underset{\text{Ethanamine}}{\mathrm{C}{\phantom{A}}_2\mathrm{H}{\phantom{A}}_5\mathrm{NH}{\phantom{A}}_2}}$$