Question

The energy density of a medium is 3.54 x 10^{- 5} J/m³. The intensity of electric field in the medium of dielectric constant 2 is ______.

Options

• 1 x 10³ N/C

• 2 x 10³ N/C

• 4 x 10³ N/C

• 8 x 10³ N/C

Answer 1

The energy density of a medium is 3.54 x 10^{- 5} J/m³. The intensity of electric field in the medium of dielectric constant 2 is 2 x 10³ N/C.

Explanation:

u = `1/2 epsilon_0  "kE"^2`

`"E"^2 = 2"u"/epsilon_0  "k" = (2xx3xx3.54xx10^-5)/(8.85xx10^-12xx12)`

` = 0.4 xx 10^7`

` = 4 xx 10^6`

` therefore "E" = sqrt(4xx10^6) = 2 xx 10^3 "N"/"C"`