Question

The equation of a line passing through the point (7, - 4) and perpendicular to the line passing through the points (2, 3) and (1 , - 2 ) is ______.

Options

• x + 5y + 13 = 0

• x - 2y - 15 =0

• x - 5y - 13 = 0

• x + 2y + 1 = 0

Answer 1

The equation of a line passing through the point (7, - 4) and perpendicular to the line passing through the points (2, 3) and (1 , - 2 ) is x + 5y + 13 = 0.

Explanation:

Equation of line passing through (7, - 4) and perpendicular to the line p~ssing through (2, 3) and (1, - 2) is

y + 4 = - `((1 - 2)/(- 2 - 3))`(x - 7)

y + 4 = `- 1/5`(x - 7)

5y + 20 = - x + 7

⇒ x + 5y + 13 = 0