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The equation of conjugate axis for the hyperbola (x+y+1)24-(x-y+2)29 = 1 is ______. -

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Question

The equation of conjugate axis for the hyperbola `(x + y + 1)^2/4 - (x - y + 2)^2/9` = 1 is ______.

Options

  • x + y + 1 = 0

  • x – y + 2 = 0

  • x = `-3/2`

  • x + y + 2 = 0

MCQ
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Solution

The equation of conjugate axis for the hyperbola `(x + y + 1)^2/4 - (x - y + 2)^2/9` = 1 is x + y + 1 = 0.

Explanation:

`(x + y + 1)^2/4 - (x - y + 2)^2/9` = 1

Let x + y + 1 = X and x – y + 2 = Y

∴ `X^2/4 - Y^2/9` = 1

Put X = 0 for the conjugate axis

∴ x + y + 1 = 0

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Conic Sections - Hyperbola
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