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The equation of line equally inclined to co-ordinate axes and passing through (–3, 2, –5) is ______. -

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Question

The equation of line equally inclined to co-ordinate axes and passing through (–3, 2, –5) is ______.

Options

  • `(x + 3)/1 = (y - 2)/1 = (z + 5)/1`

  • `(x + 3)/(-1) = (y - 2)/1 = (5 + z)/(-1)`

  • `(x + 3)/(-1) = (y - 2)/1 = (z + 5)/1`

  • `(x + 3)/(-1) = (2 - y)/1 = (z + 5)/(-1)`

MCQ
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Solution

The equation of line equally inclined to co-ordinate axes and passing through (–3, 2, –5) is

`(x + 3)/1 = (y - 2)/1 = (z + 5)/1`.

Explanation:

If a line is equally inclined to axes, then l = m = n = `+- 1/sqrt(3)`

∴ d.r.s. of the line are 1, 1, 1

Given that the line passes through the point (–3, 2, –5)

∴ The equation of line is `(x + 3)/1 = (y - 2)/1 = (z + 5)/1`.

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Vector and Cartesian Equations of a Line
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