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Question
The equation of line equally inclined to co-ordinate axes and passing through (–3, 2, –5) is ______.
Options
`(x + 3)/1 = (y - 2)/1 = (z + 5)/1`
`(x + 3)/(-1) = (y - 2)/1 = (5 + z)/(-1)`
`(x + 3)/(-1) = (y - 2)/1 = (z + 5)/1`
`(x + 3)/(-1) = (2 - y)/1 = (z + 5)/(-1)`
MCQ
Fill in the Blanks
Solution
The equation of line equally inclined to co-ordinate axes and passing through (–3, 2, –5) is
`(x + 3)/1 = (y - 2)/1 = (z + 5)/1`.
Explanation:
If a line is equally inclined to axes, then l = m = n = `+- 1/sqrt(3)`
∴ d.r.s. of the line are 1, 1, 1
Given that the line passes through the point (–3, 2, –5)
∴ The equation of line is `(x + 3)/1 = (y - 2)/1 = (z + 5)/1`.
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Vector and Cartesian Equations of a Line
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