Question

The equation of state for 2g of oxygen at a pressure 'P' and temperature 'T', when occupying a volume 'V' will be ______.

Options

• pV = 16 RT

• pV = RT

• pV = `1/16`RT

• pV = 2RT

Answer 1

The equation of state for 2g of oxygen at a pressure 'P' and temperature 'T', when occupying a volume 'V' will be pV = `1/16`RT.

Explanation:

The ideal gas equation is given by

pV = µRT      ...(i)

where, µ = number of moles in gas

As, `mu = "Given mass"/"Molecular mass" = "m"/"M"`

Here, m = 2g

and for oxygen (O₂), M = 32 g

Substituting these values in Eq. (i), we get

pV = `"m"/"M" "RT" = 2/32 "RT"`

`therefore "pV" = 1/16 "RT"`