Advertisements
Advertisements
Question
The equation of the parabola whose vertex and focus are on the positive side of the x-axis at distances a and b respectively from the origin is ______.
Options
y2 = 4(b – a)(x – a)
y2 = 4(a – b)(x – b)
x2 = 4(b – a)(y – a)
x2 = 4(a – b)(y – b)
MCQ
Fill in the Blanks
Solution
The equation of the parabola whose vertex and focus are on the positive side of the x-axis at distances a and b respectively from the origin is `underlinebb(y^2 = 4(b - a)(x - a))`.
Explanation:
Let equation of parabola is (y – y1)2 = 4A(x – x1)
Here A = (b – a)
and vertex = (x1, y1) ≡ (a, 0)
∴ Equation will be (y – 0)2 = 4(b – a)(x – a)
⇒ y2 = 4(b – a)(x – a)
shaalaa.com
Conic Sections - Parabola
Is there an error in this question or solution?