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Question
The equivalent mass of potassium permanganate in alkaline medium is \[\ce{MnO^-_4 + 2H2O + 3e^- -> MnO2 + 4OH^-}\]
Options
31.6
52.7
79
None of these
MCQ
Solution
52.7
Explanation:
The reduction reaction of the oxidising agent \[\ce{(MnO^-_4)}\] involves gain of 3 electrons.
Hence the equivalent mass = `("Molar mass of KMnO"_4)/3`
= `158.1/3`
= 52.7
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Gram Equivalent Concept
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