Question

The excess of pressure, due to surface tension, on a spherical liquid drop of radius 'R' is proportional to ______.

Options

• R^-1

• R

• R^-2

• R²

Answer 1

The excess of pressure, due to surface tension, on a spherical liquid drop of radius 'R' is proportional to R^-1.

Explanation:

The excess of pressure due to surface tension on a spherical liquid drop is given by

p = `"2T"/"R"`    ...(i)

where, T = surface tension

and R = radius of liquid drop.

So, from Eq. (i), we get

`"p" prop 1/"R"  "or"  "p" prop "R"^-1`