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The External Dimensions of a Closed Wooden Box Are 27 Cm, 19 Cm, and 11 Cm. If the Thickness of the Wood in the Box is 1.5 Cm; Find: (I) the Volume of the Wood in the Box; - Mathematics

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Question

The external dimensions of a closed wooden box are 27 cm, 19 cm, and 11 cm. If the thickness of the wood in the box is 1.5 cm; find:

  1. The volume of the wood in the box;
  2. The cost of the box, if wood costs Rs. 1.20 per cm3;
  3. A number of 4 cm cubes that could be placed into the box.
Sum

Solution

External volume of the box 
= 27 × 19  × 11 cm3 = 5643 cm3

Since external dimensions are 27 cm, 19 cm, and 11 cm, the thickness of the wood is 1.5 cm.

Internal dimensions of the box 
= ( 27 - 2  × 1.5 ) cm, ( 19 - 2  × 1.5 )cm, ( 11 - 2  × 1.5 ) cm
= 24 cm, 16 cm, 8 cm

Hence, the internal volume of box = ( 24  × 16  × 8 ) cm3 = 3072 cm3

  1. The volume of wood in the box = 5643 cm3 - 3072 cm3 = 2571 cm3
  2. Cost of wood = Rs. 1.20  × 2571
    = Rs. 3085.2
  3. Volume. of 4 cm cube = 43 = 64 cm3
  4. Number of 4 cm cubes that could be placed into the box
    = `3072/64`
    =  48 cubes.
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Chapter 21: Solids [Surface Area and Volume of 3-D Solids] - Exercise 21 (A) [Page 269]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Solids [Surface Area and Volume of 3-D Solids]
Exercise 21 (A) | Q 11 | Page 269
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