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The First (δ1h1) and the Second (δ1h2) Ionization Enthalpies (In Kj Mol-1) and the (δEgh) Electron Gain Enthalpy (In Kj Mol-1) of a Few Elements - Chemistry

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Question

The first (Δ1H1) and the second (Δ1H2) ionization enthalpies (in kJ mol-1) and the (ΔegH) electron gain enthalpy (in kJ mol-1) of a few elements are given below:

Elements Δ1H1 Δ1H2 ΔegH
I 520 7300 -60
II 419 3051 -48
III 1681 3374 -328
IV 1008 1846 -295
V 2372 5251 +48
VI 738 1451 -40

Which of the above elements is likely to be the metal which can form a stable binary halide of the formula MX2, (X=halogen).

Short Note

Solution

Element VI has a low negative electron gain enthalpy (ΔegH). Thus, it is a metal. Further, it has the lowest second ionization enthalpy (Δ1H2). Hence, it can form a stable binary halide of the formula MX2(X = halogen).

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Chapter 3: Classification of Elements and Periodicity in Properties - EXERCISES [Page 98]

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NCERT Chemistry - Part 1 and 2 [English] Class 11
Chapter 3 Classification of Elements and Periodicity in Properties
EXERCISES | Q 3.31 - (e) | Page 98

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The first (Δ1H1) and the second (Δ1H2) ionization enthalpies (in kJ mol-1) and the (ΔegH) electron gain enthalpy (in kJ mol-1) of a few elements are given below:

Elements Δ1H1 Δ1H2 ΔegH
I 520 7300 -60
II 419 3051 -48
III 1681 3374 -328
IV 1008 1846 -295
V 2372 5251 +48
VI 738 1451 -40

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Elements Δ1H1 Δ1H2 ΔegH
I 520 7300 -60
II 419 3051 -48
III 1681 3374 -328
IV 1008 1846 -295
V 2372 5251 +48
VI 738 1451 -40

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Elements Δ1H1 Δ1H2 ΔegH
I 520 7300 -60
II 419 3051 -48
III 1681 3374 -328
IV 1008 1846 -295
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VI 738 1451 -40

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Elements Δ1H1 Δ1H2 ΔegH
I 520 7300 -60
II 419 3051 -48
III 1681 3374 -328
IV 1008 1846 -295
V 2372 5251 +48
VI 738 1451 -40

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Elements Δ1H1 Δ1H2 ΔegH
I 520 7300 -60
II 419 3051 -48
III 1681 3374 -328
IV 1008 1846 -295
V 2372 5251 +48
VI 738 1451 -40

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