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Question
The following diagram shows a part of the periodic table in which the elements are arranged according to their atomic numbers. (The letters given here not the chemical symbols of the elements):
a 3 |
b 4 |
c 5 |
d 6 |
e 7 |
f 8 |
g 9 |
h 10 |
|
i 11 |
j 12 |
k 13 |
l 14 |
m 15 |
n 16 |
o 17 |
p 18 |
(i) Which element has a bigger atom, a or f?
(ii) Which element has a higher valency, k or o?
(iii) Which element is more metallic i or k?
(iv) Which element is more non-metallic, d or g?
(v) Select a latter which represents a metal of valency 2.
(vi) Select a letter which represents a non-metal of valency 2.
Solution
(i) Element a has a bigger atom. In the periodic table, the atomic radius of the element decreases on moving from left to right in a period.
(ii) k has a higher valency.
Electronic configuration of k : K L M
2 8 3
Therefore, valency for k = valence electron of K = 3
Electronic configuration of o: K L M
2 8 7
Therefore, valency for o = 8 - valence electron of o
= 8 - 7 = 1
(iii) The element i is more metallic because i belongs to the left side and group 1 of the periodic table. On moving from left to right in a period, the metallic character decreases.
(iv) The element g is more non-metallic, because the non-metallic character increases on moving from left to right in a period.
(v) The elements b or j are metals with a valency of 2 as they have 2 valence electrons and are placed on the left side of periodic table.
(vi) The elements f or n are metals with a valency of 2 .
Electronic configuration of f : K L
2 6
Valency of f = 8 - valence electron
= 8 - 6 = 2
Electronic configuration of n : K L M
2 8 6
Valency of n = 8 - valence electron
= 8 - 6 = 2
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