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The force between two small charged spheres having charges of 1 × 10−7 C and 2 × 10−7 C placed 20 cm apart in the air is: -

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Question

The force between two small charged spheres having charges of 1 × 10−7 C and 2 × 10−7 C placed 20 cm apart in the air is:

Options

  • 4.5 × 10−2 N

  • 4.5 × 10−3 N

  • 5.4 × 10−2 N

  • 5.4 × 10−3 N

MCQ

Solution

4.5 × 10−3 N

Explanation:

Here, q1 = 1 × 10−7 C, q2 = 2 × 10−7 C,

r = 20 cm = 20 × 10−2 m

F = `("q"_1"q"_2)/(4πε_0"r"^2)`

= `(9 xx 10^9 xx 1 xx 10^-7 xx 2 xx 10^-7)/((20 xx 10^-2)^2)`

= 4.5 × 10−3 N

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Superposition Principle - Forces Between Multiple Charges
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