Advertisements
Advertisements
Question
The frequency of the tuning fork is 484 Hz. What is the time period?
Short Note
Solution
Frequency of tuning fork, n = 484 Hz.
Frequency, n = `1/"T" ⇒ "T" = 1/"n"`
Time Period, T = `1/4841` = 0.00207 s.
shaalaa.com
Is there an error in this question or solution?