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Question
The fundamental frequency of an open organ pipe is 300 Hz. The first overtone of this pipe has same frequency as first overtone of a closed organ pipe. If speed of sound is 330 m/s, then the length of closed organ pipe is:
Options
41 cm
37 cm
31 cm
80 cm
MCQ
Solution
41 cm
Explanation:
For open pipe, n = `"v"/(2ℓ)`, where n0 is the fundamental frequency of open pipe.
∴ ℓ = `"v"/(2"n") = 330/(2 xx 300) = 11/20`
As freq. of 1st overtone of open pipe = freq. of 1st overtone of closed pipe
∴ `2"v"/(2ℓ) = 3"v"/(4ℓ"'")`
⇒ ℓ' = `(3ℓ)/4`
= `3/4 xx 11/20`
= 41.25 cm
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