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Question
The half-value thickness of an absorber is defined as the thickness that will reduce exponentially the intensity of a beam of particles by a factor of 2. The half-value thickness in (µm) for lead assuming X-ray beam of wavelength 20 pm, µ = 50 cm-1 for X-rays in lead at wavelength λ = 20 pm, is ______ µm.
Options
130
135
137
139
MCQ
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Solution
The half-value thickness of an absorber is defined as the thickness that will reduce exponentially the intensity of a beam of particles by a factor of 2. The half-value thickness in (µm) for lead assuming X-ray beam of wavelength 20 pm, µ = 50 cm-1 for X-rays in lead at wavelength λ = 20 pm, is 139 µm.
Explanation:
I = I0e-µx
`"I"_0/2` = I0e-µx
µx = ℓn2
x = `(ℓ"n"2)/mu`
= `0.693/50`
= 0.01386 cm
= 138.6 µm ≃ 139 µm
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