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Question
The height and radius of the cone of which the frustum is a part are h1 units and r1 units respectively. Height of the frustum is h2 units and the radius of the smaller base is r2 units. If h2 : h1 = 1 : 2 then r2 : r1 is
Options
1 : 3
1 : 2
2 : 1
3 : 1
Solution
1 : 2
Explanation;
Hint:
h2 : h1 = 1 : 2
h1 : h2 = 2 : 1
Ratio of their volumes
= `1/3 pi"h"_1 ("r"_1^2 + "r"_2^2 + "r"_1"r"_2) : 1/3pi"h"_2 ("r"_1^2 + "r"_2^2 + "r"_1"r"_2)`
= 2(r12 + r22 + r1r2) : 1 (r12 + r22 + r1r2)
Volume is 2 : 1 the ratio of their radius also 2 : 1
r1 : r2 = 2 : 1 But r2 : r1 = 1 : 2
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