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Question
The increase in energy of a metal bar of length 'L' and cross-sectional area 'A' when compressed with a load 'M' along its length is ______.
(Y = Young's modulus of the material of metal bar)
Options
`"FL"/(2"AY")`
`("F"^2"L")/(2"AY")`
`"FL"/"AY"`
`("F"^2"L"^2)/(2"AY")`
MCQ
Fill in the Blanks
Solution
The increase in energy of a metal bar of length 'L' and cross-sectional area 'A' when compressed with a load 'M' along its length is `underlinebb(("F"^2"L")/(2"AY"))`.
(Y = Young's modulus of the material of metal bar)
Explanation:
∵ Y = `"FL"/"Al"`
∴ l`"FL"/"AY"`
Work done / increase in energy
= `("YAL"^2)/(2"L")`
= `("F"^2"L")/(2"AY")`
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Diffraction of Light
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