Question

The integrating factor of the differential equation `x (dy)/(dx) - y = 2x^2` is

Options

• `e^-x`

• `e^-y`

• `1/x`

• `x`

Answer 1

`1/x`

Explanation:

`x (dy)/(dx) - y = 2x^2` or `(dy)/(dx) - 1/x y = 2x`

I.F. =`e^(int  1/x  dx)`

= `e^(-logx)`

= `e^(log  1/x)`

= `1/x`