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Question
The internal measures of a cuboidal room are 12 m × 8 m × 4 m. Find the total cost of whitewashing all four walls of a room, if the cost of whitewashing is Rs. 5 per m2. What will be the cost of whitewashing if the ceiling of the room is also whitewashed.
Sum
Solution
Let the length of the room = l = 12 m
Width of the room = b = 8 m
Height of the room = h = 4 m
Area of the four walls of the room = Perimeter of the base × Height of the room
= 2 (l + b) × h = 2 (12 + 8) × 4
= 2 × 20 × 4 = 160 m2
Cost of white washing per m2 = Rs. 5
Hence the total cost of white washing four walls of the room = Rs. (160 × 5) = Rs. 800.
Area of ceiling is 12 × 8 = 96 m2
Cost of white washing the ceiling = Rs. (96 × 5) = Rs. 480
So the total cost of white washing = Rs. (800 + 480) = Rs. 1280
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