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Question
The length of a rod is exactly 1 m when measured at rest. What will be its length when it moves at a speed of (a) 3 × 105 m s−1, (b) 3 × 106 m s−1 and (c) 3 × 107 m s−1?
Solution
Given:-
Proper length of the rod, L = 1 m
If v is the velocity of the rod, then the moving length of the rod is given by
\[L' = L\sqrt{1 - \frac{v^2}{c^2}}\]
(a) Here,
v = 3 × 105 m/s
\[L' = 1 \times \sqrt{1 - \frac{9 \times {10}^{10}}{9 \times {10}^{16}}}\]
\[ = \sqrt{1 - {10}^{- 6}} = 0 . 9999995 m\]
(b) Here,
v = 3 × 106 m/s
\[L' = 1 \times \sqrt{1 - \frac{9 \times {10}^{12}}{9 \times {10}^{16}}}\]
\[ = \sqrt{1 - {10}^{- 4}}\]
\[ = 0 . 99995 m\]
(c) Here,
v = 3 × 107 m/s
\[L' = 1 \times \sqrt{1 - \frac{9 \times {10}^{14}}{9 \times {10}^{16}}}\]
\[ = 1\sqrt{1 - {10}^{- 2}}\]
\[ = 0 . 995 m\]
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