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Question
The line 3x - 2y = 0 coincides with one of the lines given by ax2 + 2hxy + by2 = 0, then ______
Options
4a + 12h + 9b = 0
4a + 12h - 9b = 0
3a + 4h + 7b = 0
3a + 4h - 7b = 0
MCQ
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Solution
The line 3x - 2y = 0 coincides with one of the lines given by ax2 + 2hxy + by2 = 0, then 4a + 12h + 9b = 0.
Explanation:
The auxiliary form of equation ax2 + 2hxy + by2 = 0 is bm2 + 2hm + a = 0.
The slope of line 3x - 2y = 0 is m = `3/2`.
3x - 2y = 0 coincides with one of the lines given by ax2 + 2hxy + by2 = 0.
∴ Substituting m = `3/2` in auxiliary equation,
we get
`b(3/2)^2 + 2h(3/2) + a = 0`
⇒ 4a + 12h + 9b = 0
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Homogeneous Equation of Degree Two
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