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The line 3x - 2y = 0 coincides with one of the lines given by ax2 + 2hxy + by2 = 0, then ______ -

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Question

The line 3x - 2y = 0 coincides with one of the lines given by ax2 + 2hxy + by2 = 0, then ______

Options

  • 4a + 12h + 9b = 0

  • 4a + 12h - 9b = 0

  • 3a + 4h + 7b = 0

  • 3a + 4h - 7b = 0

MCQ
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Solution

The line 3x - 2y = 0 coincides with one of the lines given by ax2 + 2hxy + by2 = 0, then 4a + 12h + 9b = 0.

Explanation:

The auxiliary form of equation ax2 + 2hxy + by2 = 0 is bm2 + 2hm + a = 0.

The slope of line 3x - 2y = 0 is m = `3/2`.

3x - 2y = 0 coincides with one of the lines given by ax2 + 2hxy + by2 = 0.

∴ Substituting m = `3/2` in auxiliary equation,

we get

`b(3/2)^2 + 2h(3/2) + a = 0`

⇒ 4a + 12h + 9b = 0

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Homogeneous Equation of Degree Two
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