Question

The line at 434 nm in the Balmer series of the hydrogen spectrum corresponds to a transition of an electron from the n^th to second Bohr orbit. The value of n is ______.

Options

• 3

• 5

• 7

• 9

Answer 1

The line at 434 nm in the Balmer series of the hydrogen spectrum corresponds to a transition of an electron from the n^th to second Bohr orbit. The value of n is 5.

Explanation:

λ = 434 × 10^–9 × 10¹⁰ Å

= 43.4 Å

`1/λ = "RZ"^2 [1/"n"_1^2 - 1/"n"_2^2]` .....(i)

n₁ = 2

n₂ = n

Solving the (i) equation we can get n = 5