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Question
The line is y = x + 1 is a tangent to the curve y2 = 4x at the point.
Options
(1, 2)
(2, 1)
(1, –2)
(–1, 2)
MCQ
Solution
(1, 2)
Explanation:
The Curve is `y^2 = 4x, 2y (dy)/(dx)` = 4
∴ `(dy)/(dx) = 2/(2y) = 2/y`
Slope of the given line, `y = x + 1` is 1.
∴ `2/y` = 1, ∴ `y` = 2
Putting `y` = 2 in `y^2 = 4x`
`2^2 = 4x`, ∴ `x` = 1
∴ Point of contact is (1, 2).
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