Question

The linear equation that converts Fahrenheit (F) to Celsius (C) is given by the relation C = `(5F - 160)/9`. If the temperature is 0°C what is the temperature in Fahrenheit and if the temperature is 0°F, what is the temperature in Celsius?

Answer 1

Given relation is, C = `(5F - 160)/9`  ......(i)

⇒ 9C = 5F – 160 

⇒ 5F = 9C + 160

⇒ F = `(9C + 160)/5`  .....(ii)

Given, C = 0°C, then from equation (ii), we get

F = 0°F, then from equation (i), we get

F = (9 xx 0 + 160)/5`

= `160/5`

= 32°F

F = 0°F, then from equation (i), we get

C = `(5 xx 0 - 160)/9`

= `(-160)/9`

= `(- 160/9)^circ C`