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Question
The locus of a point that is equidistant from the lines `x + y - 2sqrt(2)` = 0 and `x + y - sqrt(2)` = 0 is ______.
Options
`x + y - 5sqrt(2)` = 0
`x + y - sqrt(2)` = 0
`2x + 2y - 3sqrt(2)` = 0
`2x + 2y - 5sqrt(2)` = 0
MCQ
Fill in the Blanks
Solution
The locus of a point that is equidistant from the lines `x + y - 2sqrt(2)` = 0 and `x + y - sqrt(2)` = 0 is `underlinebb(2x + 2y - 3sqrt(2) = 0)`.
Explanation:
For any point P(x, y) that is equidistant from the given line, we have
`x + y - sqrt(2) = -(x + y - 2sqrt(2))`
or `2x + 2y - 3sqrt(2)` = 0.
shaalaa.com
Equation of Locus
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