Question

The magnitude of the torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians) ______.

Options

• `pi/6`

• `pi/3`

• `pi/8`

• `pi/4`

Answer 1

The magnitude of the torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians) `underlinebb(pi/6)`.

Explanation:

Torque about the origin = `vectau = vecr xx vecF`

= r F sinθ ⇒ 2.5 = 1 × 5 sinθ

sinθ = 0.5 = `1/2`

⇒ `theta = pi/6`