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Question
The main scale of a spectrometer is divided into 720 division in all. If circular vernier scale consists of 30 divisions, the least count of the instrument is ______.
(Given: 30 vernier divisions coincide with 29 main scale divisions)
Options
0.1°
1''
1'
0.1''
Solution
The main scale of a spectrometer is divided into 720 division in all. If circular vernier scale consists of 30 divisions, the least count of the instrument is 1'.
Explanation:
Given, Total number of main scale division in spectrometer = 720
Total angle in main scale = 360°
Total angle required for the 720 main scale division = 360°
So, angle required for 1 main scale division
`(360°)/720=(1°)/2`
But, we know that 1° = 60 '
So, angle required for 1 main scale division
= `(60')/2` = 30'
As per the condition, 30 Vernier Scale Division (VSD) = 29 Main Scale Division (MSD)
1 VSD = `29/30` MSD
Least Count (LC) = 1MSD – 1VSD
LC = 1 - `29/30=1/30`
So, total angle in one least count
= `1/30` × 30' = 1'
Hence, the least count will be 1'.