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Question
The mass of a lead piece is 115 g. When it is immersed into a measuring cylinder, the water level rises from 20 ml mark to 30 ml mark.
Find the volume of the lead piece.
Solution
Given , M = 115 g
`"V"_1` = 20 ml , `"V"_2` = 30 ml
Volume of lead piece V = `"V"_2` - `"V"_1`
= 30 ml - 20 ml
= 10 ml or 10 `"cm"^3`
[ ∴ 1 ml = 1 `"cm"^3`]
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