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Question
The maximum speed of a particle in S.H.M. is 'V'. The average speed is ______
Options
`(2V)/pi^2`
`(2pi)/V`
2V2/π
2V/π
MCQ
Fill in the Blanks
Solution
The maximum speed of a particle in S.H.M. is 'V'. The average speed is 2V/π.
Explanation:
Maximum speed V = Aω where A is the amplitude and ω angular frequency
Average speed VA = `"Total distance"/"Total time" = (4A)/T`
where T = `(2pi)/omega` = Period of S.H.M.
∴ VA = `(4Aomega)/(2pi) = (2Aomega)/pi = (2V)/pi`
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Acceleration (a), Velocity (v) and Displacement (x) of S.H.M.
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