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Question
The mean of a, b, c, d and e is 28. If the mean of a, c, and e is 24, What is the mean of band d?
Options
31
32
33
34
Solution
Given that the mean of a, b, c, d and e is 28. They are 5 in numbers.
Hence, we have
`(a +b+c+d+e)/5 =28`
`⇒((a +c+e)+(b+d))/5=28`
`⇒(a+c+e)/5 +(b+d)/5 = 28`
But, it is given that the mean of a, c and e is 24. Hence, we have
`⇒(a+c+e)/3 =24`
`⇒a+c+e+=72`
Then, we have
`72/5 + (b+d)/5 =28`
`⇒(b+d)/5 =28 -72/5`
`⇒(b+d)/5 = 28-14.4`
`⇒(b+d)/5 = 13.6`
`⇒b+d = 68`
`⇒(b+d)/2 =68/2`
`⇒(b+d)/2 = 34`
Hence, the mean of b and d is 34 .
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