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Question
The mean and variance of 10 observations were calculated as 15 and 15 respectively by a student who took by mistake 25 instead of 15 for one observation. Then, the correct standard deviation is ______.
Options
0
1
2
3
Solution
The mean and variance of 10 observations were calculated as 15 and 15 respectively by a student who took by mistake 25 instead of 15 for one observation. Then, the correct standard deviation is 2.
Explanation:
Given n = 10, `barx` = 15
σ2 = 15
`barx = (sumx_i)/10` = 15
σ2 = `(sumx_i^2)/10 - (barx)^2` = 15
⇒ `sum^10x_i` = 150
⇒ `sum_(i = 1)^9x_i + 25` = 150
⇒ `sum_(i = 1)^9x_i` = 125
⇒ `sum_(i = 1)^9x_i + 15` = 140
Actual mean = `140/10` = 14 = `barx_"new"`
`sum_(i = 1)^9 (x_i^2 + 25^2 - 15^2)/10` = 15
⇒ `sum_(i = 1)^9x_i^2 + 625` = 2400
⇒ `sum_(i = 1)^9x_i^2` = 1775
⇒ `sum_(i = 1)^9x_i^2 + 15^2` = 2000
= `(sumx_i^2)_"original"`
`σ_"original"^2 = ((sumx_i^2)_"original" - (barx_"new")^2)/10`
= `2000/10 - 14^2`
= 200 – 196
= 4
`("S.D")_"original"` = 6 = 2