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The mean and variance of a random variable having a binomial distribution are 4 and 2 respectively, then P(X = 1) is ______. -

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Question

The mean and variance of a random variable having a binomial distribution are 4 and 2 respectively, then P(X = 1) is ______.

Options

  • `1/32`

  • `1/16`

  • `1/8`

  • `1/4`

MCQ
Fill in the Blanks

Solution

The mean and variance of a random variable having a binomial distribution are 4 and 2 respectively, then P(X = 1) is `underlinebb(1/32)`.

Explanation:

Mean = np = 4    ...(1)

Variance = npq = 2    ...(2)

From (1) and (2):

`(npq)/(np) = 2/4`

∴ q = `1/2`,

p = `1 - 1/2 = 1/2`

From (1):

`n(1/2)` = 4,

∴ n = 8

∴ P(X = 1) = `""^8C_1(1/2)(1/2)^7`

= `8 xx 1/(2)^8`

= `1/32`

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Mean of Binomial Distribution (P.M.F.)
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