English

The molar conductivities at infinite dilution for sodium acetate, HCI and NaCl are 91 S cm2 mol-1, 425.9 S cm2 mol-1 and 126.4 S cm2 mol-1 respectively. The molar conductivity of acetic acid -

Advertisements
Advertisements

Question

The molar conductivities at infinite dilution for sodium acetate, HCI and NaCl are 91 S cm2 mol-1, 425.9 S cm2 mol-1 and 126.4 S cm2 mol-1 respectively. The molar conductivity of acetic acid at infinite dilution is ______.

Options

  • 390.5 S cm2 mol-1

  • 530.9 S cm2 mol-1

  • 300.5 S cm2 mol-1

  • 930.5 S cm2 mol-1

MCQ
Fill in the Blanks

Solution

The molar conductivities at infinite dilution for sodium acetate, HCI and NaCl are 91 S cm2 mol-1, 425.9 S cm2 mol-1 and 126.4 S cm2 mol-1 respectively. The molar conductivity of acetic acid at infinite dilution is 390.5 S cm2 mol-1.

Explanation:

Given, `∧_("m"(NaAc))^circ` = 91 S cm2 mol-1 

`∧_("m"(HCl))^circ` = 425.9 S cm2 mol-1 

`∧_("m"(NaCl))^circ` = 126.4 S cm2 mol-1 

Using Kohlrausch law, to find the molar conductivity of acetic acid.

`∧_("m"(HaC))^circ = lambda_("H"^+)^circ + lambda_("AC"^-)^circ`

`= lambda_("H"^+)^circ + lambda_("Cl"^-)^circ + lambda_("AC"^-)^circ + lambda_("Na"^+)^circ - lambda_("Cl"^-)^circ - lambda_("Na"^+)^circ`

`∧_("m"(HCl))^circ + ∧_("m"(NaAc))^circ - ∧_("m"(NaCl))^circ`

= (425.9 + 91.0 - 126.4) S cm2 mol-1

= 390.5 S cm2 mol-1

shaalaa.com
Electrical Conductance of Solution
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×