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Question
The molar specific heat of He at constant volume is 12.47 J/mol.K. Two moles of He are heated at constant pressure. So the rise in temperature is 10 K. Find the increase in internal energy of the gas.
Numerical
Solution
Given: Cv= 12.4 7 J /mol.K, n = 2, Tf -Ti = 10 K
To find: The increase in the internal energy of the gas (ΔU) = ?
ΔU = nCv (Tf - Ti)
= 2 × 12.47 × 10
= 249.4 J
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