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Question
The moment of a force of 25 N about a point is 2.5 N m. Find the perpendicular distance of force from that point.
Solution
Moment of force = 2.5 N m
Force applied = 25
⊥ distance from the point of rotation?
Moment of force = Force × ⊥ distance
2.5 = 25 × χ
∴ x = ⊥ distance = `2.5/25=1/10 m`
= 1/10 × 100 = 10 m
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