Question

The momentum of a photon of energy 1 MeV in kg m/s will be ______

Options

• 5 x 10^-22

• 0.33 x 10⁶

• 7 x 10^-24

• 10^-22

Answer 1

The momentum of a photon of energy 1 MeV in kg m/s will be 5 x 10^-22.

Explanation:

E = 1 MeV, p = `"E"/"c" = (1 xx 10^6 xx 1.6 xx 10^-19)/(3 xx 10^8)`

= 0.53 × 10^-21

= 5 × 10^-22 kg m/s