Question

The nature of hybridisation in the ammonia molecule is

Options

• sp²

• dp²

• sp

• sp³

Answer 1

sp³ 

Explanation:

The hybridisation in a molecule is given by H = \[\ce{1/2 [V + M - C + A]}\] 

Where V = no. of valency e– in central atom

M = no. of monovalent atoms around central atom

C = charge on cation, A = change on anion

For NH₃; V = 5, M = 3, C = 0, A = 0

Putting these values in (i), we get

H = \[\ce{1/2 [5 + 3 - 0 + 0] = 4}\] 

For H = 4, the hybridisation in molecule is sp³.