Advertisements
Advertisements
Question
The normal pressure of air is 76 cm of mercury. Calculate the pressure in SI units.
[Density of mercury = 13600 kg/m3 and g = 10 m/s2]
Solution
Height of mercury column = h = 76 cm
h = 0.76 m
Density of mercury =ρ = 13600 kg/m3
Acceleration due to gravity = g = 10 m/s2
Pressure = P = ?
P = hρg
P = 0.76 × 13600 × 10 = 103360 N/m2
APPEARS IN
RELATED QUESTIONS
What vertical height of water will exert a pressure of 333200 Pa? The density of water is 1000 kgnr3 and g = 9.8 ms−2.
Pressure at the bottom of the sea at some particular place is 8968960 Pa. If the density of seawater is 1040 kgm3 calculate the depth of the sea. Take g = 9.8 ms−2. Neglect the pressure of the atmosphere.
Calculate the equivalent height of mercury, which will exert as much pressure as 960 m of seawater of density 1040 kgm−3. The density of mercury is 13600 kgm−3.
What do you mean by relative density?
